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<blockquote data-quote="AUDIOLYTIC" data-source="post: 1058621056" data-attributes="member: 25217"><p><strong>Απάντηση: Re: Rega vs Rega tonearm !!!!!</strong></p><p></p><p></p><p></p><p>Βρηκα αυτο που ειχα αποθηκευμενο , ελπιζω να σου ειναι χρησιμο.Αναφερει και τις παραμετρους που λαμβανει υπ'οψιν.</p><p>Δεν ξερω πως θα φανει, το εκανα copy paste διοτι δεν ανεβαινε διαφορετικα.Καπου πρεπει να εχω και αλλα ,αν τα πετυχω τα ανεβαζω.</p><p>Ειναι απο καποιον που μεταφρασε στα Αγγλικα απο τη γλωσσα του, και ισως εχει και καποια "περιεργα" στη μεταφραση.</p><p></p><p> </p><p></p><p></p><p>"Slightly simplified but very useful formula for calculating the effective mass of the arm:</p><p></p><p>M = [(w*r^2)/L^2]+[(2wr)/3L]</p><p></p><p>M - mass effective</p><p>w - mass counterweight balancing arm without padding</p><p>r - distance from the point of suspension of a counterweight (the best counterweight to hang by a thread, then you will see a counterweight suspension point) from the pivot point of the beam.</p><p>L - effective length of arm</p><p></p><p>This formula is simplified - assumes equal distribution of weight on the shoulder pads and leaves a negligible effect on the weight of the counterbalance beam. This formula does not require the weighing arm enough to take a counterbalance to the store and weigh. If someone has an arm with a variable diameter or want a more accurate model can make changes. That is why I've included departure.</p><p></p><p>Moment of inertia on the side of a counterweight is equal [to]</p><p></p><p>w*r^2</p><p></p><p>Moment of inertia on the side of the insert is equal to</p><p></p><p></p><p>(m*L^2) / 3</p><p></p><p>where m is the mass of the beam arm on the side of the insert.</p><p></p><p>In the balanced arm (without pad) moments of forces on both sides of the bearing are equal, so:</p><p></p><p>m * (L/2) = w * r</p><p></p><p>ie</p><p></p><p>m = (2wr)/L</p><p></p><p>Moment of inertia caused by the effective mass is equal to the sum of the moments of inertia of the arm on both sides, so:</p><p></p><p>M * L^2 = [w * r^2] + [(m * L^2) / 3] = [w * r^2] + [(2wrL) / 3]</p><p></p><p>M = [(w * r^2) / L^2] + [(2wr) / 3L]</p><p></p><p></p><p>III.</p><p>Reduced model of the relationship between the total effective mass of the arm (ie the sum of the effective mass of the arm, mass inserts and screws) and the resonant frequency of the arm pad fz susceptibility c:</p><p></p><p>Ms = 25356 / (c*f^2)</p><p></p><p>The above formula can also calculate the frequency f or the susceptibility c as you know the rest of the data."</p></blockquote><p></p>
[QUOTE="AUDIOLYTIC, post: 1058621056, member: 25217"] [b]Απάντηση: Re: Rega vs Rega tonearm !!!!![/b] Βρηκα αυτο που ειχα αποθηκευμενο , ελπιζω να σου ειναι χρησιμο.Αναφερει και τις παραμετρους που λαμβανει υπ'οψιν. Δεν ξερω πως θα φανει, το εκανα copy paste διοτι δεν ανεβαινε διαφορετικα.Καπου πρεπει να εχω και αλλα ,αν τα πετυχω τα ανεβαζω. Ειναι απο καποιον που μεταφρασε στα Αγγλικα απο τη γλωσσα του, και ισως εχει και καποια "περιεργα" στη μεταφραση. "Slightly simplified but very useful formula for calculating the effective mass of the arm: M = [(w*r^2)/L^2]+[(2wr)/3L] M - mass effective w - mass counterweight balancing arm without padding r - distance from the point of suspension of a counterweight (the best counterweight to hang by a thread, then you will see a counterweight suspension point) from the pivot point of the beam. L - effective length of arm This formula is simplified - assumes equal distribution of weight on the shoulder pads and leaves a negligible effect on the weight of the counterbalance beam. This formula does not require the weighing arm enough to take a counterbalance to the store and weigh. If someone has an arm with a variable diameter or want a more accurate model can make changes. That is why I've included departure. Moment of inertia on the side of a counterweight is equal [to] w*r^2 Moment of inertia on the side of the insert is equal to (m*L^2) / 3 where m is the mass of the beam arm on the side of the insert. In the balanced arm (without pad) moments of forces on both sides of the bearing are equal, so: m * (L/2) = w * r ie m = (2wr)/L Moment of inertia caused by the effective mass is equal to the sum of the moments of inertia of the arm on both sides, so: M * L^2 = [w * r^2] + [(m * L^2) / 3] = [w * r^2] + [(2wrL) / 3] M = [(w * r^2) / L^2] + [(2wr) / 3L] III. Reduced model of the relationship between the total effective mass of the arm (ie the sum of the effective mass of the arm, mass inserts and screws) and the resonant frequency of the arm pad fz susceptibility c: Ms = 25356 / (c*f^2) The above formula can also calculate the frequency f or the susceptibility c as you know the rest of the data." [/QUOTE]
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